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6x^2+78x+132=0
a = 6; b = 78; c = +132;
Δ = b2-4ac
Δ = 782-4·6·132
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(78)-54}{2*6}=\frac{-132}{12} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(78)+54}{2*6}=\frac{-24}{12} =-2 $
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